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16/04/2018 at 4:20pm

A little monkey had 60 peaches.

On the first day he decided to keep 3/4

of his peaches. He gave the rest away. Then he ate one.

On the second day he decided to keep 7/11

of his peaches. He gave the rest away. Then he ate one.

of his peaches. He gave the rest away. Then he ate one.

On the third day he decided to keep 5/9

of his peaches. He gave the rest away. Then he ate one.

On the fourth day he decided to keep 2/7

of his peaches. He gave the rest away. Then he ate one.

of his peaches. He gave the rest away. Then he ate one.

On the fifth day he decided to keep 2/3

of his peaches. He gave the rest away. Then he ate one.

How many did he have left at the end?

2 Teams Points for first correct solution handed in WITH your working out.

## Comments that people have made about this blog post

Day 2: 44 divided by 11=4. 4x7=28. 28-1=27

Day 3: 27 divided by 9=3. 3x5=15. 15-1=14

Day 4: 14 divided by 7=2. 2x2=4. 4-1=3

Day 5: 3 divided by 3=1. 1x2=2. 2-1=1

Answer=1

P.S I cheated a little bit with help from my Mum!!!!!!