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Fraction Puzzle

A little monkey had 60 peaches.

On the first day he decided to keep 3/4
of his peaches. He gave the rest away. Then he ate one.

On the second day he decided to keep 7/11
of his peaches. He gave the rest away. Then he ate one.

On the third day he decided to keep 5/9
of his peaches. He gave the rest away. Then he ate one.

On the fourth day he decided to keep 2/7
of his peaches. He gave the rest away. Then he ate one.

On the fifth day he decided to keep 2/3
of his peaches. He gave the rest away. Then he ate one.

How many did he have left at the end?

2 Teams Points for first correct solution handed in WITH your working out.

Comments that people have made about this blog post

Comment 1 Comment by Lucy B on 03 Dec 12 at 7:28pm | Quote this comment
Day 1: 60 divided by 4=15. 15x3=45. 45-1=44
Day 2: 44 divided by 11=4. 4x7=28. 28-1=27
Day 3: 27 divided by 9=3. 3x5=15. 15-1=14
Day 4: 14 divided by 7=2. 2x2=4. 4-1=3
Day 5: 3 divided by 3=1. 1x2=2. 2-1=1

Answer=1

P.S I cheated a little bit with help from my Mum!!!!!! :lol:
Comment 2 Comment by Mr Brooks on 04 Dec 12 at 7:09am | Quote this comment
Well done Lucy. One TP. Can anyone else write a fraction problem along the same lines as these.

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